2014年4月27日 星期日

[LeetCode] Clone Graph

Problem:
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.

OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.
Visually, the graph looks like the following:
       1
      / \
     /   \
    0 --- 2
         / \
         \_/
Solution:O(n)
public class Solution {
   static HashMap map = new HashMap();
   public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
      if(node == null)
         return null;
         
      UndirectedGraphNode rnode = new UndirectedGraphNode(node.label);
        
      for(UndirectedGraphNode nnode:node.neighbors){
         if(nnode != node){
            UndirectedGraphNode mynode = null;
            if(map.get(nnode)!=null ){
               mynode = map.get(nnode);
            }else{
               mynode = cloneGraph(nnode);
            }
            rnode.neighbors.add(mynode);
         }
         else{
            rnode.neighbors.add(rnode); 
         }
      }
      map.put(node, rnode);
      return rnode;
   }
}

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