Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:Given the below binary tree and
sum = 22
,5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1
return true, as there exist a root-to-leaf path
5->4->11->2
which sum is 22.
Solution:O(n)
public class Solution {
public boolean hasPathSum(TreeNode root, int sum) {
if(root == null){
return false;
}
if(root.left == null && root.right == null && root.val == sum)
return true;
else{
return hasPathSum(root.left, sum-root.val) || hasPathSum(root.right, sum-root.val) ;
}
}
}
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