The string
"PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)P A H N A P L S I I G Y I RAnd then read line by line:
"PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)
should return "PAHNAPLSIIGYIR"
.Solution:O(n)
public class Solution {
public String convert(String s, int nRows) {
if(s == null || s.length()==0 )
return "";
if(nRows == 1)
return s;
int bsize = 2* nRows-2;
String ret = "";
char set[] = s.toCharArray();
int bb = s.length()/bsize;
if(s.length() % bsize !=0)
bb+=1;
for(int i=0; i<nRows;i++){
for(int t=0; t< bb;t++){
if(t*bsize+i >= set.length)
break;
int index = t*bsize+i;
ret += set[index];
if(i != 0 && i != (nRows-1)){
int rindex = bsize*(2*t+1) - index;
if(rindex <set.length)
ret += set[rindex];
}
}
}
return ret;
}
}
Note: The concept is to find the regularity about the sequence.
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